Optimal. Leaf size=408 \[ \frac{5 (b c-a d)^{9/2} ((a+b x) (c+d x))^{3/4} \sqrt{(a d+b c+2 b d x)^2} \left (\frac{2 \sqrt{b} \sqrt{d} \sqrt{(a+b x) (c+d x)}}{b c-a d}+1\right ) \sqrt{\frac{(a d+b (c+2 d x))^2}{(b c-a d)^2 \left (\frac{2 \sqrt{b} \sqrt{d} \sqrt{(a+b x) (c+d x)}}{b c-a d}+1\right )^2}} \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{b} \sqrt [4]{d} \sqrt [4]{(a+b x) (c+d x)}}{\sqrt{b c-a d}}\right ),\frac{1}{2}\right )}{168 \sqrt{2} b^{9/4} d^{9/4} (a+b x)^{3/4} (c+d x)^{3/4} (a d+b c+2 b d x) \sqrt{(a d+b (c+2 d x))^2}}-\frac{5 \sqrt [4]{a+b x} \sqrt [4]{c+d x} (b c-a d)^3}{84 b^2 d^2}+\frac{(a+b x)^{5/4} \sqrt [4]{c+d x} (b c-a d)^2}{42 b^2 d}+\frac{(a+b x)^{9/4} \sqrt [4]{c+d x} (b c-a d)}{7 b^2}+\frac{2 (a+b x)^{9/4} (c+d x)^{5/4}}{7 b} \]
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Rubi [A] time = 0.590231, antiderivative size = 408, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 4, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.21, Rules used = {50, 62, 623, 220} \[ -\frac{5 \sqrt [4]{a+b x} \sqrt [4]{c+d x} (b c-a d)^3}{84 b^2 d^2}+\frac{5 (b c-a d)^{9/2} ((a+b x) (c+d x))^{3/4} \sqrt{(a d+b c+2 b d x)^2} \left (\frac{2 \sqrt{b} \sqrt{d} \sqrt{(a+b x) (c+d x)}}{b c-a d}+1\right ) \sqrt{\frac{(a d+b (c+2 d x))^2}{(b c-a d)^2 \left (\frac{2 \sqrt{b} \sqrt{d} \sqrt{(a+b x) (c+d x)}}{b c-a d}+1\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{b} \sqrt [4]{d} \sqrt [4]{(a+b x) (c+d x)}}{\sqrt{b c-a d}}\right )|\frac{1}{2}\right )}{168 \sqrt{2} b^{9/4} d^{9/4} (a+b x)^{3/4} (c+d x)^{3/4} (a d+b c+2 b d x) \sqrt{(a d+b (c+2 d x))^2}}+\frac{(a+b x)^{5/4} \sqrt [4]{c+d x} (b c-a d)^2}{42 b^2 d}+\frac{(a+b x)^{9/4} \sqrt [4]{c+d x} (b c-a d)}{7 b^2}+\frac{2 (a+b x)^{9/4} (c+d x)^{5/4}}{7 b} \]
Antiderivative was successfully verified.
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Rule 50
Rule 62
Rule 623
Rule 220
Rubi steps
\begin{align*} \int (a+b x)^{5/4} (c+d x)^{5/4} \, dx &=\frac{2 (a+b x)^{9/4} (c+d x)^{5/4}}{7 b}+\frac{(5 (b c-a d)) \int (a+b x)^{5/4} \sqrt [4]{c+d x} \, dx}{14 b}\\ &=\frac{(b c-a d) (a+b x)^{9/4} \sqrt [4]{c+d x}}{7 b^2}+\frac{2 (a+b x)^{9/4} (c+d x)^{5/4}}{7 b}+\frac{(b c-a d)^2 \int \frac{(a+b x)^{5/4}}{(c+d x)^{3/4}} \, dx}{28 b^2}\\ &=\frac{(b c-a d)^2 (a+b x)^{5/4} \sqrt [4]{c+d x}}{42 b^2 d}+\frac{(b c-a d) (a+b x)^{9/4} \sqrt [4]{c+d x}}{7 b^2}+\frac{2 (a+b x)^{9/4} (c+d x)^{5/4}}{7 b}-\frac{\left (5 (b c-a d)^3\right ) \int \frac{\sqrt [4]{a+b x}}{(c+d x)^{3/4}} \, dx}{168 b^2 d}\\ &=-\frac{5 (b c-a d)^3 \sqrt [4]{a+b x} \sqrt [4]{c+d x}}{84 b^2 d^2}+\frac{(b c-a d)^2 (a+b x)^{5/4} \sqrt [4]{c+d x}}{42 b^2 d}+\frac{(b c-a d) (a+b x)^{9/4} \sqrt [4]{c+d x}}{7 b^2}+\frac{2 (a+b x)^{9/4} (c+d x)^{5/4}}{7 b}+\frac{\left (5 (b c-a d)^4\right ) \int \frac{1}{(a+b x)^{3/4} (c+d x)^{3/4}} \, dx}{336 b^2 d^2}\\ &=-\frac{5 (b c-a d)^3 \sqrt [4]{a+b x} \sqrt [4]{c+d x}}{84 b^2 d^2}+\frac{(b c-a d)^2 (a+b x)^{5/4} \sqrt [4]{c+d x}}{42 b^2 d}+\frac{(b c-a d) (a+b x)^{9/4} \sqrt [4]{c+d x}}{7 b^2}+\frac{2 (a+b x)^{9/4} (c+d x)^{5/4}}{7 b}+\frac{\left (5 (b c-a d)^4 ((a+b x) (c+d x))^{3/4}\right ) \int \frac{1}{\left (a c+(b c+a d) x+b d x^2\right )^{3/4}} \, dx}{336 b^2 d^2 (a+b x)^{3/4} (c+d x)^{3/4}}\\ &=-\frac{5 (b c-a d)^3 \sqrt [4]{a+b x} \sqrt [4]{c+d x}}{84 b^2 d^2}+\frac{(b c-a d)^2 (a+b x)^{5/4} \sqrt [4]{c+d x}}{42 b^2 d}+\frac{(b c-a d) (a+b x)^{9/4} \sqrt [4]{c+d x}}{7 b^2}+\frac{2 (a+b x)^{9/4} (c+d x)^{5/4}}{7 b}+\frac{\left (5 (b c-a d)^4 ((a+b x) (c+d x))^{3/4} \sqrt{(b c+a d+2 b d x)^2}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{-4 a b c d+(b c+a d)^2+4 b d x^4}} \, dx,x,\sqrt [4]{(a+b x) (c+d x)}\right )}{84 b^2 d^2 (a+b x)^{3/4} (c+d x)^{3/4} (b c+a d+2 b d x)}\\ &=-\frac{5 (b c-a d)^3 \sqrt [4]{a+b x} \sqrt [4]{c+d x}}{84 b^2 d^2}+\frac{(b c-a d)^2 (a+b x)^{5/4} \sqrt [4]{c+d x}}{42 b^2 d}+\frac{(b c-a d) (a+b x)^{9/4} \sqrt [4]{c+d x}}{7 b^2}+\frac{2 (a+b x)^{9/4} (c+d x)^{5/4}}{7 b}+\frac{5 (b c-a d)^{9/2} ((a+b x) (c+d x))^{3/4} \sqrt{(b c+a d+2 b d x)^2} \left (1+\frac{2 \sqrt{b} \sqrt{d} \sqrt{(a+b x) (c+d x)}}{b c-a d}\right ) \sqrt{\frac{(a d+b (c+2 d x))^2}{(b c-a d)^2 \left (1+\frac{2 \sqrt{b} \sqrt{d} \sqrt{(a+b x) (c+d x)}}{b c-a d}\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{b} \sqrt [4]{d} \sqrt [4]{(a+b x) (c+d x)}}{\sqrt{b c-a d}}\right )|\frac{1}{2}\right )}{168 \sqrt{2} b^{9/4} d^{9/4} (a+b x)^{3/4} (c+d x)^{3/4} (b c+a d+2 b d x) \sqrt{(a d+b (c+2 d x))^2}}\\ \end{align*}
Mathematica [C] time = 0.0583903, size = 73, normalized size = 0.18 \[ \frac{4 (a+b x)^{9/4} (c+d x)^{5/4} \, _2F_1\left (-\frac{5}{4},\frac{9}{4};\frac{13}{4};\frac{d (a+b x)}{a d-b c}\right )}{9 b \left (\frac{b (c+d x)}{b c-a d}\right )^{5/4}} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.029, size = 0, normalized size = 0. \begin{align*} \int \left ( bx+a \right ) ^{{\frac{5}{4}}} \left ( dx+c \right ) ^{{\frac{5}{4}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b x + a\right )}^{\frac{5}{4}}{\left (d x + c\right )}^{\frac{5}{4}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (b d x^{2} + a c +{\left (b c + a d\right )} x\right )}{\left (b x + a\right )}^{\frac{1}{4}}{\left (d x + c\right )}^{\frac{1}{4}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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